(7x+5)=(2x-35)

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Solution for (7x+5)=(2x-35) equation: 



(7x+5)=(2x-35)

We move all terms to the left:

(7x+5)-((2x-35))=0

We get rid of parentheses

7x-((2x-35))+5=0



We calculate terms in parentheses: -((2x-35)), so:

(2x-35)

We get rid of parentheses

2x-35

Back to the equation:

-(2x-35)



We get rid of parentheses

7x-2x+35+5=0

We add all the numbers together, and all the variables

5x+40=0

We move all terms containing x to the left, all other terms to the right

5x=-40

x=-40/5

x=-8

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