10-(20x+5)=-4(10x+6)-331

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Solution for 10-(20x+5)=-4(10x+6)-331 equation: 



10-(20x+5)=-4(10x+6)-331

We move all terms to the left:

10-(20x+5)-(-4(10x+6)-331)=0

We get rid of parentheses

-20x-(-4(10x+6)-331)-5+10=0



We calculate terms in parentheses: -(-4(10x+6)-331), so:

-4(10x+6)-331

We multiply parentheses

-40x-24-331

We add all the numbers together, and all the variables

-40x-355

Back to the equation:

-(-40x-355)



We add all the numbers together, and all the variables

-20x-(-40x-355)+5=0

We get rid of parentheses

-20x+40x+355+5=0

We add all the numbers together, and all the variables

20x+360=0

We move all terms containing x to the left, all other terms to the right

20x=-360

x=-360/20

x=-18

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