25x-x2=

Solution for 25x-x2= equation:

25x-x2=

We move all terms to the left:

25x-x2-()=0

We add all the numbers together, and all the variables

-1x^2+25x=0

a = -1; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-1)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-1}=\frac{-50}{-2}
=+25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-1}=\frac{0}{-2}
=0
$