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10+x=5(1/5x+20
We move all terms to the left:
10+x-(5(1/5x+20)=0
Domain of the equation: 5x+20)+10!=0We multiply all the terms by the denominator
x∈R
x*5x+20)+10-(5(1=0
We add all the numbers together, and all the variables
x*5x=0
Wy multiply elements
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{10}=0$
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