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10+3(x+5)=8-(2x-7)
We move all terms to the left:
10+3(x+5)-(8-(2x-7))=0
We multiply parentheses
3x-(8-(2x-7))+15+10=0
We calculate terms in parentheses: -(8-(2x-7)), so:We add all the numbers together, and all the variables
8-(2x-7)
determiningTheFunctionDomain -(2x-7)+8
We get rid of parentheses
-2x+7+8
We add all the numbers together, and all the variables
-2x+15
Back to the equation:
-(-2x+15)
3x-(-2x+15)+25=0
We get rid of parentheses
3x+2x-15+25=0
We add all the numbers together, and all the variables
5x+10=0
We move all terms containing x to the left, all other terms to the right
5x=-10
x=-10/5
x=-2
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