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(3x-3)+(7x+23)=180
We move all terms to the left:
(3x-3)+(7x+23)-(180)=0
We get rid of parentheses
3x+7x-3+23-180=0
We add all the numbers together, and all the variables
10x-160=0
We move all terms containing x to the left, all other terms to the right
10x=160
x=160/10
x=16
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