10(z+9)=8-(-10z-82)

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Solution for 10(z+9)=8-(-10z-82) equation: 



10(z+9)=8-(-10z-82)

We move all terms to the left:

10(z+9)-(8-(-10z-82))=0

We multiply parentheses

10z-(8-(-10z-82))+90=0



We calculate terms in parentheses: -(8-(-10z-82)), so:

8-(-10z-82)

determiningTheFunctionDomain
-(-10z-82)+8

We get rid of parentheses

10z+82+8

We add all the numbers together, and all the variables

10z+90

Back to the equation:

-(10z+90)



We get rid of parentheses

10z-10z-90+90=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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