(-1/2)b=2

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Solution for (-1/2)b=2 equation: 



(-1/2)b=2

We move all terms to the left:

(-1/2)b-(2)=0



Domain of the equation: 2)b!=0

b!=0/1

b!=0

b∈R



We multiply parentheses

-1b^2-2=0

a = -1; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-1)·(-2)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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