10(z+1)=3(z-3)

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Solution for 10(z+1)=3(z-3) equation: 



10(z+1)=3(z-3)

We move all terms to the left:

10(z+1)-(3(z-3))=0

We multiply parentheses

10z-(3(z-3))+10=0



We calculate terms in parentheses: -(3(z-3)), so:

3(z-3)

We multiply parentheses

3z-9

Back to the equation:

-(3z-9)



We get rid of parentheses

10z-3z+9+10=0

We add all the numbers together, and all the variables

7z+19=0

We move all terms containing z to the left, all other terms to the right

7z=-19

z=-19/7

z=-2+5/7

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