5(2x+1)=6(3x-4)+7

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Solution for 5(2x+1)=6(3x-4)+7 equation: 



5(2x+1)=6(3x-4)+7

We move all terms to the left:

5(2x+1)-(6(3x-4)+7)=0

We multiply parentheses

10x-(6(3x-4)+7)+5=0



We calculate terms in parentheses: -(6(3x-4)+7), so:

6(3x-4)+7

We multiply parentheses

18x-24+7

We add all the numbers together, and all the variables

18x-17

Back to the equation:

-(18x-17)



We get rid of parentheses

10x-18x+17+5=0

We add all the numbers together, and all the variables

-8x+22=0

We move all terms containing x to the left, all other terms to the right

-8x=-22

x=-22/-8

x=2+3/4

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