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10(y+1)=5(2y+2)
We move all terms to the left:
10(y+1)-(5(2y+2))=0
We multiply parentheses
10y-(5(2y+2))+10=0
We calculate terms in parentheses: -(5(2y+2)), so:We get rid of parentheses
5(2y+2)
We multiply parentheses
10y+10
Back to the equation:
-(10y+10)
10y-10y-10+10=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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