10(x+3/5)=2

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Solution for 10(x+3/5)=2 equation:



10(x+3/5)=2
We move all terms to the left:
10(x+3/5)-(2)=0
We add all the numbers together, and all the variables
10(+x+3/5)-2=0
We multiply parentheses
10x-2+3/5*10=0
We multiply all the terms by the denominator
10x*5*10+3-2*5*10=0
We add all the numbers together, and all the variables
10x*5*10-97=0
Wy multiply elements
500x*1-97=0
Wy multiply elements
500x-97=0
We move all terms containing x to the left, all other terms to the right
500x=97
x=97/500
x=97/500

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