1/z=(6/5z)+1

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Solution for 1/z=(6/5z)+1 equation: 



1/z=(6/5z)+1

We move all terms to the left:

1/z-((6/5z)+1)=0



Domain of the equation: z!=0

z∈R





Domain of the equation: 5z)+1)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

1/z-((+6/5z)+1)=0

We calculate fractions


5z/5z^2+(-((+6*z)/5z^2=0

We add all the numbers together, and all the variables

5z/5z^2+(-((+6z)/5z^2=0

We multiply all the terms by the denominator


5z+(-((+6z)=0



We calculate terms in parentheses: +(-((+6z), so:

-((+6z





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