10(x+3)=2(3x+5)

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Solution for 10(x+3)=2(3x+5) equation: 



10(x+3)=2(3x+5)

We move all terms to the left:

10(x+3)-(2(3x+5))=0

We multiply parentheses

10x-(2(3x+5))+30=0



We calculate terms in parentheses: -(2(3x+5)), so:

2(3x+5)

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

10x-6x-10+30=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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