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3x=9x^2-30
We move all terms to the left:
3x-(9x^2-30)=0
We get rid of parentheses
-9x^2+3x+30=0
a = -9; b = 3; c = +30;
Δ = b2-4ac
Δ = 32-4·(-9)·30
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*-9}=\frac{-36}{-18} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*-9}=\frac{30}{-18} =-1+2/3 $
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