10(x+2)=(6x+12)

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Solution for 10(x+2)=(6x+12) equation: 



10(x+2)=(6x+12)

We move all terms to the left:

10(x+2)-((6x+12))=0

We multiply parentheses

10x-((6x+12))+20=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

10x-6x-12+20=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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