10(x+2)=3(6x+12)

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Solution for 10(x+2)=3(6x+12) equation: 



10(x+2)=3(6x+12)

We move all terms to the left:

10(x+2)-(3(6x+12))=0

We multiply parentheses

10x-(3(6x+12))+20=0



We calculate terms in parentheses: -(3(6x+12)), so:

3(6x+12)

We multiply parentheses

18x+36

Back to the equation:

-(18x+36)



We get rid of parentheses

10x-18x-36+20=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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