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10(v+2)-4v=2(3v+1)-3
We move all terms to the left:
10(v+2)-4v-(2(3v+1)-3)=0
We add all the numbers together, and all the variables
-4v+10(v+2)-(2(3v+1)-3)=0
We multiply parentheses
-4v+10v-(2(3v+1)-3)+20=0
We calculate terms in parentheses: -(2(3v+1)-3), so:We add all the numbers together, and all the variables
2(3v+1)-3
We multiply parentheses
6v+2-3
We add all the numbers together, and all the variables
6v-1
Back to the equation:
-(6v-1)
6v-(6v-1)+20=0
We get rid of parentheses
6v-6v+1+20=0
We add all the numbers together, and all the variables
21!=0
There is no solution for this equation
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