10(n+2)=6(n-2)

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Solution for 10(n+2)=6(n-2) equation: 



10(n+2)=6(n-2)

We move all terms to the left:

10(n+2)-(6(n-2))=0

We multiply parentheses

10n-(6(n-2))+20=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We get rid of parentheses

10n-6n+12+20=0

We add all the numbers together, and all the variables

4n+32=0

We move all terms containing n to the left, all other terms to the right

4n=-32

n=-32/4

n=-8

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