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6(x+1)=3(x+3)
We move all terms to the left:
6(x+1)-(3(x+3))=0
We multiply parentheses
6x-(3(x+3))+6=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
6x-3x-9+6=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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