10(c-5)+8=3+c-45

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Solution for 10(c-5)+8=3+c-45 equation: 



10(c-5)+8=3+c-45

We move all terms to the left:

10(c-5)+8-(3+c-45)=0

We add all the numbers together, and all the variables

10(c-5)-(c-42)+8=0

We multiply parentheses

10c-(c-42)-50+8=0

We get rid of parentheses

10c-c+42-50+8=0

We add all the numbers together, and all the variables

9c=0

c=0/9

c=0

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