z/(z+12)=3/5

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Solution for z/(z+12)=3/5 equation: 



z/(z+12)=3/5

We move all terms to the left:

z/(z+12)-(3/5)=0



Domain of the equation: (z+12)!=0

We move all terms containing z to the left, all other terms to the right

z!=-12

z∈R



We add all the numbers together, and all the variables

z/(z+12)-(+3/5)=0

We get rid of parentheses

z/(z+12)-3/5=0

We calculate fractions


5z/(5z+60)+(-3z-36)/(5z+60)=0

We multiply all the terms by the denominator


5z+(-3z-36)=0

We get rid of parentheses

5z-3z-36=0

We add all the numbers together, and all the variables

2z-36=0

We move all terms containing z to the left, all other terms to the right

2z=36

z=36/2

z=18

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