10(4a+6)=6(6a-10)=4a

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Solution for 10(4a+6)=6(6a-10)=4a equation: 



10(4a+6)=6(6a-10)=4a

We move all terms to the left:

10(4a+6)-(6(6a-10))=0

We multiply parentheses

40a-(6(6a-10))+60=0



We calculate terms in parentheses: -(6(6a-10)), so:

6(6a-10)

We multiply parentheses

36a-60

Back to the equation:

-(36a-60)



We get rid of parentheses

40a-36a+60+60=0

We add all the numbers together, and all the variables

4a+120=0

We move all terms containing a to the left, all other terms to the right

4a=-120

a=-120/4

a=-30

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