10(x+6/2)=10(x-3/5)

Solution for 10(x+6/2)=10(x-3/5) equation:

10(x+6/2)=10(x-3/5)

We move all terms to the left:

10(x+6/2)-(10(x-3/5))=0

We add all the numbers together, and all the variables

10(x+3)-(10(+x-3/5))=0

We multiply parentheses

10x-(10(+x-3/5))+30=0

We multiply all the terms by the denominator


10x*5))-(10(+x-3+30*5))=0

We add all the numbers together, and all the variables

10x*5))-(10(x+147))=0

We add all the numbers together, and all the variables

10x*5))-(10(x=0

Wy multiply elements

50x^2=0

a = 50; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·50·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{100}=0$