10(3y+1)=-20

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Solution for 10(3y+1)=-20 equation: 



10(3y+1)=-20

We move all terms to the left:

10(3y+1)-(-20)=0

We add all the numbers together, and all the variables

10(3y+1)+20=0

We multiply parentheses

30y+10+20=0

We add all the numbers together, and all the variables

30y+30=0

We move all terms containing y to the left, all other terms to the right

30y=-30

y=-30/30

y=-1

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