11=(3/5)*(6x+10)

Solution for 11=(3/5)*(6x+10) equation:

11=(3/5)(6x+10)

We move all terms to the left:

11-((3/5)(6x+10))=0


Domain of the equation: 5)(6x+10))!=0

x∈R


We add all the numbers together, and all the variables

-((+3/5)(6x+10))+11=0

We multiply parentheses ..

-((+18x^2+3/5*10))+11=0

We multiply all the terms by the denominator


-((+18x^2+3+11*5*10))=0


We calculate terms in parentheses: -((+18x^2+3+11*5*10)), so:

(+18x^2+3+11*5*10)

We get rid of parentheses

18x^2+3+11*5*10

We add all the numbers together, and all the variables

18x^2+553

Back to the equation:

-(18x^2+553)


We get rid of parentheses

-18x^2-553=0

a = -18; b = 0; c = -553;
Δ = b2-4ac
Δ = 02-4·(-18)·(-553)
Δ = -39816
Delta is less than zero, so there is no solution for the equation