10(3c-6)-3(c+7)=9(c-10)

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Solution for 10(3c-6)-3(c+7)=9(c-10) equation: 



10(3c-6)-3(c+7)=9(c-10)

We move all terms to the left:

10(3c-6)-3(c+7)-(9(c-10))=0

We multiply parentheses

30c-3c-(9(c-10))-60-21=0



We calculate terms in parentheses: -(9(c-10)), so:

9(c-10)

We multiply parentheses

9c-90

Back to the equation:

-(9c-90)



We add all the numbers together, and all the variables

27c-(9c-90)-81=0

We get rid of parentheses

27c-9c+90-81=0

We add all the numbers together, and all the variables

18c+9=0

We move all terms containing c to the left, all other terms to the right

18c=-9

c=-9/18

c=-1/2

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