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10(3-y)+2(y-2)=6(2y-2)
We move all terms to the left:
10(3-y)+2(y-2)-(6(2y-2))=0
We add all the numbers together, and all the variables
10(-1y+3)+2(y-2)-(6(2y-2))=0
We multiply parentheses
-10y+2y-(6(2y-2))+30-4=0
We calculate terms in parentheses: -(6(2y-2)), so:We add all the numbers together, and all the variables
6(2y-2)
We multiply parentheses
12y-12
Back to the equation:
-(12y-12)
-8y-(12y-12)+26=0
We get rid of parentheses
-8y-12y+12+26=0
We add all the numbers together, and all the variables
-20y+38=0
We move all terms containing y to the left, all other terms to the right
-20y=-38
y=-38/-20
y=1+9/10
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