(b-3)/(4)=(b-7)/(3)

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Solution for (b-3)/(4)=(b-7)/(3) equation: 



(b-3)/(4)=(b-7)/(3)

We move all terms to the left:

(b-3)/(4)-((b-7)/(3))=0

We calculate fractions


b/()+(-((b-7)*4)/()=0



We calculate terms in parentheses: +(-((b-7)*4)/(), so:

-((b-7)*4)/(

We multiply all the terms by the denominator


-((b-7)*4)



We calculate terms in parentheses: -((b-7)*4), so:

(b-7)*4

We multiply parentheses

4b-28

Back to the equation:

-(4b-28)



We get rid of parentheses

-4b+28

Back to the equation:

+(-4b+28)



We get rid of parentheses

b/()-4b+28=0

We multiply all the terms by the denominator


b-4b*()+28*()=0

We add all the numbers together, and all the variables

b-4b*()=0

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