10(2y-2)-y=2(9y-8)

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Solution for 10(2y-2)-y=2(9y-8) equation: 



10(2y-2)-y=2(9y-8)

We move all terms to the left:

10(2y-2)-y-(2(9y-8))=0

We add all the numbers together, and all the variables

-1y+10(2y-2)-(2(9y-8))=0

We multiply parentheses

-1y+20y-(2(9y-8))-20=0



We calculate terms in parentheses: -(2(9y-8)), so:

2(9y-8)

We multiply parentheses

18y-16

Back to the equation:

-(18y-16)



We add all the numbers together, and all the variables

19y-(18y-16)-20=0

We get rid of parentheses

19y-18y+16-20=0

We add all the numbers together, and all the variables

y-4=0

We move all terms containing y to the left, all other terms to the right

y=4

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