10(1+3x)+x=20-x

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Solution for 10(1+3x)+x=20-x equation: 



10(1+3x)+x=20-x

We move all terms to the left:

10(1+3x)+x-(20-x)=0

We add all the numbers together, and all the variables

10(3x+1)+x-(-1x+20)=0

We add all the numbers together, and all the variables

x+10(3x+1)-(-1x+20)=0

We multiply parentheses

x+30x-(-1x+20)+10=0

We get rid of parentheses

x+30x+1x-20+10=0

We add all the numbers together, and all the variables

32x-10=0

We move all terms containing x to the left, all other terms to the right

32x=10

x=10/32

x=5/16

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