12(x-2)+3x=1/2(x+6)+12

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Solution for 12(x-2)+3x=1/2(x+6)+12 equation: 



12(x-2)+3x=1/2(x+6)+12

We move all terms to the left:

12(x-2)+3x-(1/2(x+6)+12)=0



Domain of the equation: 2(x+6)+12)!=0

x∈R



We add all the numbers together, and all the variables

3x+12(x-2)-(1/2(x+6)+12)=0

We multiply parentheses

3x+12x-(1/2(x+6)+12)-24=0

We multiply all the terms by the denominator


3x*2(x+6)+12)+12x*2(x+6)+12)-(1-24*2(x+6)+12)=0

We add all the numbers together, and all the variables

3x*2(x+6)+12)+12x*2(x+6)+12)-(1-24*2(x=0

Wy multiply elements

6x^2(x+12)+12x*2(x+6)-24*2(x+12)-(1=0

We add all the numbers together, and all the variables

6x^2(x+12)+12x*2(x+6)-24*2(x+12)=0

Wy multiply elements

6x^2(x+12)+24x^2(x-48x(x=0

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