10(-3-2t)=10-2(6t-13)=0

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Solution for 10(-3-2t)=10-2(6t-13)=0 equation: 



10(-3-2t)=10-2(6t-13)=0

We move all terms to the left:

10(-3-2t)-(10-2(6t-13))=0

We add all the numbers together, and all the variables

10(-2t-3)-(10-2(6t-13))=0

We multiply parentheses

-20t-(10-2(6t-13))-30=0



We calculate terms in parentheses: -(10-2(6t-13)), so:

10-2(6t-13)

determiningTheFunctionDomain
-2(6t-13)+10

We multiply parentheses

-12t+26+10

We add all the numbers together, and all the variables

-12t+36

Back to the equation:

-(-12t+36)



We get rid of parentheses

-20t+12t-36-30=0

We add all the numbers together, and all the variables

-8t-66=0

We move all terms containing t to the left, all other terms to the right

-8t=66

t=66/-8

t=-8+1/4

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