1/x=2/(x+1)

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Solution for 1/x=2/(x+1) equation: 



1/x=2/(x+1)

We move all terms to the left:

1/x-(2/(x+1))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


(1*(x+1)))/2x^2+(-(2*x)/2x^2=0

We add all the numbers together, and all the variables

(1*(x+1)))/2x^2+(-(+2x)/2x^2=0

We calculate fractions


((1*(x+1)))*2x^2)/(2x^2+(*2x^2)+(-(+2x)*2x^2)/(2x^2+(*2x^2)=0



We calculate terms in parentheses: +(-(+2x)*2x^2)/(2x^2+(*2x^2), so:

-(+2x)*2x^2)/(2x^2+(*2x^2

We multiply all the terms by the denominator


-(+2x)*2x^2)+((*2x^2)*(2x^2

Back to the equation:

+(-(+2x)*2x^2)+((*2x^2)*(2x^2)



We get rid of parentheses

((1*(x+1)))*2x^2)/(2x^2+*2x^2+(-(+2x)*2x^2)+((*2x^2)*2x^2=0

We multiply all the terms by the denominator


((1*(x+1)))*2x^2)+(*2x^2)*(2x^2+((-(+2x)*2x^2))*(2x^2+(((*2x^2)*2x^2)*(2x^2=0

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