(-7p-2)(2p-7)=0

Solution for (-7p-2)(2p-7)=0 equation:

(-7p-2)(2p-7)=0

We multiply parentheses ..

(-14p^2+49p-4p+14)=0

We get rid of parentheses

-14p^2+49p-4p+14=0

We add all the numbers together, and all the variables

-14p^2+45p+14=0

a = -14; b = 45; c = +14;
Δ = b2-4ac
Δ = 452-4·(-14)·14
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-53}{2*-14}=\frac{-98}{-28}
=3+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+53}{2*-14}=\frac{8}{-28}
=-2/7
$