1/x-4-5/x+2=6/(x-4)(x+2)

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Solution for 1/x-4-5/x+2=6/(x-4)(x+2) equation: 



1/x-4-5/x+2=6/(x-4)(x+2)

We move all terms to the left:

1/x-4-5/x+2-(6/(x-4)(x+2))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-4)(x+2))!=0

x∈R



We add all the numbers together, and all the variables

1/x-5/x-(6/(x-4)(x+2))-2=0

We multiply parentheses ..

-(6/(+x^2+2x-4x-8))+1/x-5/x-2=0

We calculate fractions

We do not support expression: x^3

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