-6(-2x+2)4(3+4x)-6=28

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Solution for -6(-2x+2)4(3+4x)-6=28 equation: 



-6(-2x+2)4(3+4x)-6=28

We move all terms to the left:

-6(-2x+2)4(3+4x)-6-(28)=0

We add all the numbers together, and all the variables

-6(-2x+2)4(4x+3)-6-28=0

We add all the numbers together, and all the variables

-6(-2x+2)4(4x+3)-34=0

We move all terms containing x to the left, all other terms to the right

-6(-2x+2)4(4x+3)=34

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