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1/x+5/4x=1/2
We move all terms to the left:
1/x+5/4x-(1/2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
1/x+5/4x-(+1/2)=0
We get rid of parentheses
1/x+5/4x-1/2=0
We calculate fractions
(-16x^2)/16x^2+16x/16x^2+20x/16x^2=0
We multiply all the terms by the denominator
(-16x^2)+16x+20x=0
We add all the numbers together, and all the variables
(-16x^2)+36x=0
We get rid of parentheses
-16x^2+36x=0
a = -16; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-16)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-16}=\frac{-72}{-32} =2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-16}=\frac{0}{-32} =0 $
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