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4a+3(a+1)=15-(3a-3)
We move all terms to the left:
4a+3(a+1)-(15-(3a-3))=0
We multiply parentheses
4a+3a-(15-(3a-3))+3=0
We calculate terms in parentheses: -(15-(3a-3)), so:We add all the numbers together, and all the variables
15-(3a-3)
determiningTheFunctionDomain -(3a-3)+15
We get rid of parentheses
-3a+3+15
We add all the numbers together, and all the variables
-3a+18
Back to the equation:
-(-3a+18)
7a-(-3a+18)+3=0
We get rid of parentheses
7a+3a-18+3=0
We add all the numbers together, and all the variables
10a-15=0
We move all terms containing a to the left, all other terms to the right
10a=15
a=15/10
a=1+1/2
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