1/x+2/(x+1)=5/6

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Solution for 1/x+2/(x+1)=5/6 equation: 



1/x+2/(x+1)=5/6

We move all terms to the left:

1/x+2/(x+1)-(5/6)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



We add all the numbers together, and all the variables

1/x+2/(x+1)-(+5/6)=0

We get rid of parentheses

1/x+2/(x+1)-5/6=0

We calculate fractions


(-5x^2*()/(6x^2+6x)+(6x+6)/(6x^2+6x)+72x/(6x^2+6x)=0



We calculate terms in parentheses: +(-5x^2*()/(6x^2+6x)+(6x+6)/(6x^2+6x)+72x/(6x^2+6x), so:

-5x^2*()/(6x^2+6x)+(6x+6)/(6x^2+6x)+72x/(6x^2+6x

We calculate fractions

We do not support expression: x^3

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