n/2(168+3n-3)=250

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Solution for n/2(168+3n-3)=250 equation: 



n/2(168+3n-3)=250

We move all terms to the left:

n/2(168+3n-3)-(250)=0



Domain of the equation: 2(168+3n-3)!=0

n∈R



We add all the numbers together, and all the variables

n/2(3n+165)-250=0

We multiply all the terms by the denominator


n-250*2(3n+165)=0

Wy multiply elements

n-500n(3=0

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