1/x+1/2x+1=7/10

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Solution for 1/x+1/2x+1=7/10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+1/x+1 = 7/10 // - 7/10

(1/2)*x+1/x-(7/10)+1 = 0

(1/2)*x+1/x-7/10+1 = 0

1/2*x^1+1*x^-1+3/10*x^0 = 0

(1/2*x^2+3/10*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2+3/10*x^1+1*x^0) = 0

x^1

(1/2)*x^2+(3/10)*x+1 = 0

(1/2)*x^2+(3/10)*x+1 = 0

DELTA = (3/10)^2-(1*4*(1/2))

DELTA = -191/100

DELTA < 0

x in { } 

x belongs to the empty set

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