1/x+(3/(x-6))=0

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Solution for 1/x+(3/(x-6))=0 equation: 



1/x+(3/(x-6))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-6))!=0

x∈R



We calculate fractions


-5x^2)+((3*x)/(-5x^2)+(1*(x-6)))/(=0

We add all the numbers together, and all the variables

-5x^2)+((+3x)/(-5x^2)+(1*(x-6)))/(=0

We calculate fractions


(-5x^2)+((+3x)*()/((-5x^2)*()+(-5x^2)+(1*(x-6)))*()/((-5x^2)*()=0



We calculate terms in parentheses: +((+3x)*()/((-5x^2)*()+(-5x^2)+(1*(x-6)))*()/((-5x^2)*(), so:

(+3x)*()/((-5x^2)*()+(-5x^2)+(1*(x-6)))*()/((-5x^2)*(

We can not solve this equation

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