1/x+3/(x-6)=0

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Solution for 1/x+3/(x-6)=0 equation: 



1/x+3/(x-6)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-6)!=0

We move all terms containing x to the left, all other terms to the right

x!=6

x∈R



We calculate fractions


(1*(x-6))/(x^2-6x)+3x/(x^2-6x)=0



We calculate terms in parentheses: +(1*(x-6))/(x^2-6x), so:

1*(x-6))/(x^2-6x

We add all the numbers together, and all the variables

-6x+1*(x-6))/(x^2

We multiply all the terms by the denominator


-6x*(x^2+1*(x-6))

Back to the equation:

+(-6x*(x^2+1*(x-6)))



We multiply all the terms by the denominator


((-6x*(x^2+1*(x-6))))*(x^2-6x)+3x=0



We calculate terms in parentheses: +((-6x*(x^2+1*(x-6))))*(x^2-6x), so:

(-6x*(x^2+1*(x-6))))*(x^2-6x

We add all the numbers together, and all the variables

-6x+(-6x*(x^2+1*(x-6))))*(x^2

Back to the equation:

+(-6x+(-6x*(x^2+1*(x-6))))*(x^2)



We add all the numbers together, and all the variables

3x+(-6x+(-6x*(x^2+1*(x-6))))*x^2=0

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