1/9c+1/3c=1/3

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Solution for 1/9c+1/3c=1/3 equation:



1/9c+1/3c=1/3
We move all terms to the left:
1/9c+1/3c-(1/3)=0
Domain of the equation: 9c!=0
c!=0/9
c!=0
c∈R
Domain of the equation: 3c!=0
c!=0/3
c!=0
c∈R
We add all the numbers together, and all the variables
1/9c+1/3c-(+1/3)=0
We get rid of parentheses
1/9c+1/3c-1/3=0
We calculate fractions
27c/243c^2+9c/243c^2+(-9c)/243c^2=0
We multiply all the terms by the denominator
27c+9c+(-9c)=0
We add all the numbers together, and all the variables
36c+(-9c)=0
We get rid of parentheses
36c-9c=0
We add all the numbers together, and all the variables
27c=0
c=0/27
c=0
Równanie nie ma rozwiązania

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