4(3y-1)=11y-3(y-4)

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Solution for 4(3y-1)=11y-3(y-4) equation: 



4(3y-1)=11y-3(y-4)

We move all terms to the left:

4(3y-1)-(11y-3(y-4))=0

We multiply parentheses

12y-(11y-3(y-4))-4=0



We calculate terms in parentheses: -(11y-3(y-4)), so:

11y-3(y-4)

We multiply parentheses

11y-3y+12

We add all the numbers together, and all the variables

8y+12

Back to the equation:

-(8y+12)



We get rid of parentheses

12y-8y-12-4=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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