1/9(a+8)=1/2(6-a)

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Solution for 1/9(a+8)=1/2(6-a) equation: 



1/9(a+8)=1/2(6-a)

We move all terms to the left:

1/9(a+8)-(1/2(6-a))=0



Domain of the equation: 9(a+8)!=0

a∈R





Domain of the equation: 2(6-a))!=0

a∈R



We add all the numbers together, and all the variables

1/9(a+8)-(1/2(-1a+6))=0

We calculate fractions


(2a(-)/(9(a+8)*2(-1a+6)))+(-9aa/(9(a+8)*2(-1a+6)))=0



We calculate terms in parentheses: +(2a(-)/(9(a+8)*2(-1a+6))), so:

2a(-)/(9(a+8)*2(-1a+6))

We add all the numbers together, and all the variables

2a0/(9(a+8)*2(-1a+6))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-9aa/(9(a+8)*2(-1a+6))), so:

-9aa/(9(a+8)*2(-1a+6))

We multiply all the terms by the denominator


-9aa

Back to the equation:

+(-9aa)



We get rid of parentheses

2a-9aa=0

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