-3(b+2)=3(1-2b)

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Solution for -3(b+2)=3(1-2b) equation: 



-3(b+2)=3(1-2b)

We move all terms to the left:

-3(b+2)-(3(1-2b))=0

We add all the numbers together, and all the variables

-3(b+2)-(3(-2b+1))=0

We multiply parentheses

-3b-(3(-2b+1))-6=0



We calculate terms in parentheses: -(3(-2b+1)), so:

3(-2b+1)

We multiply parentheses

-6b+3

Back to the equation:

-(-6b+3)



We get rid of parentheses

-3b+6b-3-6=0

We add all the numbers together, and all the variables

3b-9=0

We move all terms containing b to the left, all other terms to the right

3b=9

b=9/3

b=3

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