1/9(4w-32)=1/3(4w+8)

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Solution for 1/9(4w-32)=1/3(4w+8) equation: 



1/9(4w-32)=1/3(4w+8)

We move all terms to the left:

1/9(4w-32)-(1/3(4w+8))=0



Domain of the equation: 9(4w-32)!=0

w∈R





Domain of the equation: 3(4w+8))!=0

w∈R



We calculate fractions


(3w4/(9(4w-32)*3(4w+8)))+(-9w4/(9(4w-32)*3(4w+8)))=0



We calculate terms in parentheses: +(3w4/(9(4w-32)*3(4w+8))), so:

3w4/(9(4w-32)*3(4w+8))

We multiply all the terms by the denominator


3w4

We add all the numbers together, and all the variables

3w^4

We do not support ewpression: w^4

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