13-(2x+2)=2(x+20+3x)

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Solution for 13-(2x+2)=2(x+20+3x) equation: 



13-(2x+2)=2(x+20+3x)

We move all terms to the left:

13-(2x+2)-(2(x+20+3x))=0

We add all the numbers together, and all the variables

-(2x+2)-(2(4x+20))+13=0

We get rid of parentheses

-2x-(2(4x+20))-2+13=0



We calculate terms in parentheses: -(2(4x+20)), so:

2(4x+20)

We multiply parentheses

8x+40

Back to the equation:

-(8x+40)



We add all the numbers together, and all the variables

-2x-(8x+40)+11=0

We get rid of parentheses

-2x-8x-40+11=0

We add all the numbers together, and all the variables

-10x-29=0

We move all terms containing x to the left, all other terms to the right

-10x=29

x=29/-10

x=-2+9/10

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